Hrqls: You want to roll a 1 on two consecutive rolls? Assuming it's ok to roll a pair of 1s, then your calculation of 11/36 * 11/36 (about 0.0933) is correct. So you have about a nine and one third percent chance of rolling at least one 1 on two consecutive turns.

Remember, probability (or chance) is winners divided by total. In this case, a winner is a roll containing a 1, and you were correct that there are eleven of them. There are thirty six total ways of rolling a pair of dice.

Also, when dealing with two disjoint probabilities, simply multiply them together (as you did).

Hope that hleps.