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21. Maj 2008, 22:57:47
Thad 
Emne: Re:
Kili: The probability of getting exactly ten doubles in 45 throws is (1/6)^10*(5/6)^35 = 2.79990879 × 10^-11.

The probability of getting exactly five double-6s in exactly ten doubles in 45 throws is (1/36)^6*(5/36)^4*(5/6)^35 = 2.89408577 × 10^-16.

Someone correct me if I'm wrong. ;-)

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