mctrivia: That's basically what I said. However, that doesn't take SB into account - which is what nabla wants.

I don't know of an efficient algorithm that will determine whether there's a winner, even if the winner has to be decided on SB points. Sure, trying all outcomes of a match may work, but that's a lot of combinations. Take for instance a tournament with 6 players, every one playing two games against each other. All games are finished, except for one player, he hasn't finished any game yet. Then there are 7,776 different ways of the 10 games to finish (well, 59,049, but you don't have to consider player A winning one game and losing the other game against player B separately). In a group of 8, there would be 279,936 possibilities (4,782,969 without eliminating symmetries).