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 Logik

Logik.


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31. 一月 2007, 15:58:30
Czuch 
I guess I am confused where, if I guess all red, and my opponent has used one red, then I have one guess that is the correct color and is in the right position, and 4 colors that are the right color but in the wrong position. Why only one black peg then?

Say for example my opponent has a red one in the last position and I guess that color in the first position, I will get a white peg for that, but if I guess a red one in both the first and last positions, The one in the first position doesnt get anything this time?

31. 一月 2007, 16:04:37
coan.net 
题目: Re:
Czuch Czuckers: example: you guess all red - opponent has 1 red in code

You get 1 black peg since one of your guesses match the opponents pieces as the same color & same place.

You can not get more then 1 peg for each of your guesses. Black pegs overrule.

.... wait, let me explain this differently.

First thing computer does is looks for exact matches in your guess and opponenets placement. If the computer finds an exact match (same color & same position), the computer gives you a black peg and from that point on ignores that position.

So from then on, the computer only looks at the remaining 4 positions.

After the computer finds no more exact matches (black pegs), it then starts to look for any color matches in the wrong position (again, only at the 4 remaining positions) If it finds any, it will then give you a white peg and then "ignore" those pieces in the rest of it's findings.

31. 一月 2007, 16:11:53
Czuch 
题目: Re:
BIG BAD WOLF: Thanks, I think that helps a little, i will just have to play some more and figure it all out!

So, if my opponent uses all red and I use two reds in my guess, I will know that I have two colors correct and in the correct position, but I will not know for sure if either one of the red ones are correct or not?

31. 一月 2007, 16:20:46
coan.net 
题目: Re:
Czuch Czuckers: That is correct.

If your opponenets code is all red,

And your guess is red, white, black, blue, red - you will get 2 black pegs for having 2 pieces the correct color & in the correct position.

Sometimes a very tricky code can be one that has 3-4 of the same color in it! (or course on the flip side it may make it very easy on your opponent.)

31. 一月 2007, 16:25:46
Czuch 
题目: Re:
BIG BAD WOLF: So, maybe you could give me a quick strategy lesson.... in your example, what would you likely play next, and why?

31. 一月 2007, 16:30:34
coan.net 
题目: Re:
Czuch Czuckers: Well I would not want to help on any ongoing games (as to not cheat), but I've played this game on other sites before playing here and have my own way of playing - when I get some more time, I'll write up a short article on how I play - maybe a new addition to brainrook.com site.

16. 二月 2007, 07:03:10
Universal Eyes 
题目: Re:Logik
Universal Eyes修改(16. 二月 2007, 07:19:31)
BIG BAD WOLF:The pegs did not go in the right position on my first finished game,if you want the game ID# when you get a correct position the peg is suppose to be placed there,which is not the case,they move from left to right regardless of the peg color.

I hope someone can clarify my mind in some way,or do i just not understand the game.

Updated to get the game ID#2282486

16. 二月 2007, 19:27:30
nivabef 
题目: Re:Logik
Universal Eyes: Yes, that's how the game is played. It tells you how many you have right but not which ones.

16. 二月 2007, 20:09:33
Universal Eyes 
题目: Re:Logik
nivabef:Thank you.

I had figured there was something wrong.

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