coan.net: I can imagine this situation ... both players have one stone on the bar and two stones on the same field in their opponent*s home area (where they block their opponent), and both keep throwing the same double, exactly that double, which they can not use because of opponents stones.
But, this cannot happen under usual bcg-rules. Because in Hyper, how could you capture opponents stone, when you need (after finishing the movement) to have one stone one the bar and the other two in your opponents home area ? It is impossible.

SL-Mark: it depends on opponent, if your opponent is a weak player, then you can have a great excess in pieces, so you can capture his base with anything you want